预充式导管冲洗器项目可行性研究报告编写日期：二零二二年三月1目录第一章总论................................................................................11.1项目概要...............................................................11.1.1项目名称..................................................................................................................11.1.2项目建设单位..........................
∮Pdt=∮IRdt=C2Us2R(1-0.5e-2t/RC)10倍,所以选择电阻额定功率科教兴国.电容两端电压:Uc(t)=Us(1-e-t/RC电容充电电流I=C(du)/(dt)=CUsd(1-e-t/RC)/dt=CUse)-t/RC那么电阻的瞬时功率:P(t)=IR=CUsRe222-2t/RCtt2∮Pdt=∮IRdt=C2Us2R(1-0.5e-2t/RC)电阻损耗:W=00电阻平均功率：P=CUsR(1-0.5e-2t/RC)/t22当t=RC时,电容电压=0.63Us；当t=2RC时,电容电压=0.86Us；当t=3RC时,电容电压=0.95Us；当t=4RC时,电容电压=0.98Us；当t=5RC时,电...
