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2C(石墨,s)+3H2(g)→C2H6(g)θθfm26rm(CHg)HH=，θθθθrmcmcm2cm262(,s)3(H,g)(CH,g)HHHH=+−石墨θfm26H(CH,g)=θfm22H(CO,g)θfm23H(HO,l)θrHm=+(1559.8)−−2(393.5)3(285.8)(1559.8)=−+−−−184.6kJmol−=−θ1cm26(CH,g)1559.8kJmolH−=−，已知θ1fm2(CO,g)393.5kJmol,H−=−θ1fm2(HO,l)285.8kJmolH−=−θfm26H(CH,g)。求例：解法1：θ1cm26(CH,g)1559.8kJmolH−=−... 2024-05-220357.61 KB12页
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